The g acceleration has a magical part.
g = π^2 = 4/sc^2 m/s2 (1 sc = 1 sacred cubit = 2/π)
On a flat surface of the Earth, the g force equals π^2 and is not related at all to the mass/radius of the Earth.
The rate of acceleration of a falling object, which acquires kinetic energy is a measure of energy flow via conduction through the ether.
Aetherometry and gravity: an introduction (section 3, Gravitational Pendulums, g related to π2)
Torricelli and the Ocean of Air: The First Measurement of Barometric Pressure
According to the official chronology of history, the effects of the "atmospheric pressure" upon a column of water of considerable height were measured as early as 1640 AD.
A column of water 32.381' (π^2 m) (cross-section 1 square inch) generates a pressure at the bottom of one atmosphere.
The magnitude of the value is exactly equal to that of the g acceleration.
Even if we take the value of 10.336 meters to be true, then 10.336/π^2 = 1.0472 which is
exactly π/3!
Under the spherical Earth hypothesis, this is supposed to be just a random coincidence.
However, this fact cannot be true.
Modern science assumes that the proportions of the ingredients of the air (distribution of gases) have varied since the formation of the Earth, yet we are to believe that now the atmospheric pressure on a column of water will generate a height of the liquid in the glass tube of exactly π^2 m (the value of the g acceleration).
In addition, there is the atmospheric escape which takes place every year.
How could these random fluctuations in the chemical composition/mass of the Earth's atmosphere have lead to the precise value of π^2 m for the height of the water in the glass tube experiment?
In the flat earth theory, this fact is easily explained: the effect of the laevorotatory waves upon the column of water (π^2 meters) will equal exactly the magnitude of the value of the g acceleration (π^2).
The height of the liquid column does not rise because of atmospheric pressure. It is an extraordinary antigravitational effect and a proof of the existence of laevorotatory subquark strings.
The standard atmosphere, defined as being exactly equal to 101,325 pascals, is the reference value for the average atmospheric pressure at sea level. A torr is fixed by definition as being precisely equal to 1/760th of a standard atmosphere. The value of a millimeter of mercury is determined by: 1) the definition of gravity, 2) to the density of mercury (13.595 078(5) g/ml @ 0 °C, NIST value), and 3) to the temperature at which mercury's density is taken. However, the barometric pressure can vary by thousands of Pa in a single week.
The older concept of a technical atmosphere was phased out even though it worked very well in practice.
What is the unit called a technical atmosphere?
Using the technical atmosphere, we get 28.96 inHg and exactly 10 meters of water.
100,000/101,325 = π^2/10
The true gravitational acceleration at the Earth's surface corresponds to the gravitational field intensity E, and not to the net resultant acceleration, which varies with latitude.
"Traditionally, this field intensity is considered to be counteracted by the centrifugal force created by the Earth's rotation; the centrifugal acceleration is zero at the poles and reaches a maximum of 0.03392 m/s^2 at the equator. One of the problems in the current understanding of gravity is that the difference between the gravitational acceleration at the poles and at the equator is greater than any centrifugal reaction can account for. This discrepancy is conventionally explained by the Earth being not a perfect sphere but an oblate spheroid, or rather a triaxial spheroid.
Assuming that g = π^2m/s^2, and taking account of the centrifugal reaction, the value of g at the equator should be 9.83568 m/s^2, whereas the measured value is far lower: 9.780524 m/s^2. Modern technology permits more exact determinations of the measured values of net g at the poles and the equator, along with better determinations of the polar and equatorial radii. This makes it possible to accurately determine the angular velocity function (Ω) that is a constituent of the gravitational field intensity. It is pointed out that if we employ the values for net g at the poles (where no centrifugal reaction exists) along with the polar radii to determine the value of Ω, and then use this value together with the known equatorial radius to determine the gravitational field intensity at the equator, this will be found to be exactly π2m/s^2, to the fourth digit!
This rules out geometric explanations for the actual value of net g at the equator, as the differences in terrestrial geometry are already taken into account. So something besides the centrifugal force or geometry must account for the counteraction of gravity at the equator by Δ = (π^2 - 0.03392) - 9.780524 = 0.05516 m/s^2."
Therefore, this extra factor (which could be accompanied by other antigravitational factors to be accounted for) has to be substracted as well from the height of the column of water.
In the end, the magnitude of the true value of g, π^2, will equal the calculated height of the column of water, or be extremely close to it.
The mysterious antigravitational factor discovered by Dr. P. Correa is directly related to the effects exerted by the ether (its angular velocity).
The sacred cubit is designated in the form of a horseshoe projection, known as the "Boss" on the face of the Granite Leaf in the Ante-Chamber of the Pyramid. By application of this unit of measurement it was discovered to be subdivided into 25 equal parts known now as: Pyramid inches.
The value chosen in 1954 by the 10th Conférence Générale des Poids et Mesures (CGPM) for the standard atmosphere is directly related to the sacred cubit.
https://www.bipm.org/jsp/en/ViewCGPMResolution.jsp?CGPM=10&RES=4
1013250 dynes per square centimetre (
101325 Pa).
4 x 101,325 = 405,300
405,300^(1/2) = 636.63176
2/π = one sacred cubit = 0.636619772
A four digit perfect match.
100,000/101,325 = 0.9869233
π^2/10 = 0.98696044
A four digit perfect match.
Dr. C. Goldblatt, one of the foremost experts on atmospheric physics in the world (Space Science and Astrobiology Division, NASA Ames Research Center) explains the total and complete random nature of the Earth's atmosphere evolution.
https://arxiv.org/pdf/1710.10557.pdf
Then, he explains these facts in the context of the faint young sun paradox:
https://www.clim-past.net/7/203/2011/cp-7-203-2011.pdf
"Geology has been viewed as a collection of events derived from insignificant causes, a string of accidents."
Yet, out of this string of accidents, we obtain a four digit perfect match between the value of the standard atmosphere and the magnitude of the g acceleration, and between the sacred cubit and the value of the standard atmosphere.
The main reason why the technical atmosphere (one kilogram-force per square centimeter) was phased out is connected in a direct way to the fact that by using this value, the figure for the column of water will be exactly 10 meters, a fact impossible to explain in the context of the random fluctuations of the atmosphere's chemical composition/mass.
980.665 mbar = 98.0665 kPa technical atm = 28.959136 inHg = 32.8093 ft of water =
10.00027464 m
The ratio 100,000/101,325 equals exactly π^2/10 (g acceleration divided by 10, the height of the column of water using the technical atmosphere).
In 1982, the International Union of Pure and Applied Chemistry (IUPAC) recommended that for the purposes of specifying the physical properties of substances, “standard pressure” should be precisely 100 kPa (1 bar) = 100,000 Pa.
http://goldbook.iupac.org/html/S/S05921.html
The missing apex of the Gizeh pyramid measures 286.1 sacred inches (7.2738 meters), where 286.1 = 450 sacred cubits, and 100 sc = 45 x 1.4134725, 141.34725 = the height of the Gizeh pyramid frustum.
727 Torr =
28.622156 inHg = 9.8839 m of water, a value very close to the g acceleration figure π^2 = 9.8696
How many inhg in 1 torr? The answer is 0.039370072825186.
One sacred inch = 0.025424 meters.
1/3.9370073 = 0.254
Now, here is another reason why the technical atmosphere was phased out.
https://www.sensorsone.com/kpa-to-mh2o-conversion-table/
The conversion factor from pascals to meters of water involves this value: 980,665 Pa (one technical atmosphere).
1/9.80665 = 0.1019716213
2/π = 0.636619772
32/100π = 0.10185916
0.1019716213 - 010185916 = 0.00011246129 = 2.861 x 0.0000393083852
1/3.93083852 = 0.2543986
0.2543986/4 = 0.063599661
Then, the conversion factor can be evidenced directly in terms of sacred cubits.
1013250 dynes per square centimetre (101325 Pa).
4 x 101,325 = 405,300
405,300^(1/2) = 636.63176
2/π = one sacred cubit = 0.636619772
101,325 = (2000/π)^2/4 + 6sc
Then, the value of the height of column of water, corresponding to 101,325 Pascals can be expressed directly in terms of sacred cubits.